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Test if a given array has the specified value stored under key. ! does not work here to access the array by variable name. So the solution here is: https://unix.stackexchange.com/questions/60584/how-to-use-a-variable-as-part-of-an-array-name/60585#60585 Signed-off-by: Jonatan Schlag <jonatan.schlag@ipfire.org> Signed-off-by: Michael Tremer <michael.tremer@ipfire.org>
42 lines
1.0 KiB
Bash
42 lines
1.0 KiB
Bash
#!/usr/bin/bash
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# Get the path of this file.
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# This ist rather complex as we do not want the calling script file
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# That why we use BASH_SOURCE[0]
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LIB_DIR="$(readlink -f "${BASH_SOURCE[0]}")"
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# In LIB_DIR is currently saved the path to this file you are currently reading
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# but we need the directory where it is located so:
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LIB_DIR="$(dirname "${LIB_DIR}")"
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. ${LIB_DIR}/lib_color.sh
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test_command() {
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if ! "$@" ; then
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echo -e "${CLR_RED_BG} Test failed: ${*} ${CLR_RESET}"
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return 1
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else
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echo -e "${CLR_GREEN_BG} Test succeded: ${*} ${CLR_RESET}"
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return 0
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fi
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}
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var_has_value() {
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[[ "${!1}" == "${2}" ]]
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}
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test_value_in_array() {
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local -n array="${1}"
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local key="${2}"
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local value="${3}"
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if [[ "${array[${key}]}" == "${value}" ]] ; then
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echo -e "${CLR_GREEN_BG}Test succeded: The array '${1}' contains the value '${value}' under the key '${key}' ${CLR_RESET}"
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return 0
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else
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echo -e "${CLR_RED_BG}Test failed: The array '${1}' contains the value '${array[${key}]}' under the key '${key} and not '${value}' ${CLR_RESET}"
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return 1
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fi
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}
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